Alkenes contain a C=C double bond, made up of:
Ο-bond (sigma bond)
Ο-bond (pi bond)
Ο-electrons are found above and below the plane of the Ο-bond.
Since Ο-electrons are more exposed, they break easily, allowing alkenes to undergo addition reactions β Β
π₯ Why does the Ο-bond break first?
π The Ο-bond is weaker than the Ο-bond, so it breaks first, allowing addition reactions to occur!
π Alkenes react easily with small molecules, breaking the Ο-bond and forming new bonds!
β
Hydrogenation (Hβ, Ni catalyst)
β
Halogenation (Clβ, Brβ)
β
Hydrogen halides (HCl, HBr)
β
Hydration (HβO, acid catalyst)
Alkenes react with hydrogen gas (Hβ)
Requires a nickel catalyst (Ni) at 423 K
Converts alkenes β alkanes
π Propene + Hydrogen β Propane
π§ Β Bromine water test:
Orange bromine water + alkeneΒ β colourless (C=C bond present β so unsaturated)
No change if alkane (C-C only β so unsaturated)
Propene + Brβ β 1,2-dibromopropane
this is an electrophilic addition reaction
Alkenes react with gaseous hydrogen halides at room temperature
Forms haloalkanes (CβX bonds)
Propene + HCl β 1-chloropropane / 2-chloropropane
π Unsymmetrical alkenes β two possible products!
Click here to see the mechanism for this electrophilic addition reaction
Alkenes + steam (HβO, g) β alcohols
Requires phosphoric acid catalyst (HβPOβ)
Propene + HβO β propan-1-ol / propan-2-ol
π‘ Sulfuric acid (HβSOβ) can also be used as the acid catalyst!